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The Iodine "Clock Reaction" Involves the Following Sequence of Reactions

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The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. 1.IO3(aq) + 5I(aq) + 6H+(aq) → 3I2(aq) + 3H2O(l)
2.I2(aq) + 2S2O32(aq) → 2I(aq) + S4O62aq)
The molecular iodine (I2) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. What is the overall reaction occurring in this experiment?


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