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Determine How Much Energy Is Released When Thorium-230 Decays According

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Determine how much energy is released when thorium-230 decays according to the following equation. Determine how much energy is released when thorium-230 decays according to the following equation.     (1 kg = 6.022 × 10<sup>26</sup> amu; N<sub>A</sub> = 6.022 × 10<sup>23</sup> mol<sup>-1</sup>; C = 2.99792458 × 10<sup>8</sup> m/s)  A)  3.98 × 10<sup>9</sup> kJ/mol B)  4.61 × 10<sup>8</sup> kJ/mol C)  7.20 × 10<sup>11</sup> kJ/mol D)  4.90 × 10<sup>9</sup> kJ/mol E)  7.15 × 10<sup>11</sup> kJ/mol Determine how much energy is released when thorium-230 decays according to the following equation.     (1 kg = 6.022 × 10<sup>26</sup> amu; N<sub>A</sub> = 6.022 × 10<sup>23</sup> mol<sup>-1</sup>; C = 2.99792458 × 10<sup>8</sup> m/s)  A)  3.98 × 10<sup>9</sup> kJ/mol B)  4.61 × 10<sup>8</sup> kJ/mol C)  7.20 × 10<sup>11</sup> kJ/mol D)  4.90 × 10<sup>9</sup> kJ/mol E)  7.15 × 10<sup>11</sup> kJ/mol (1 kg = 6.022 × 1026 amu; NA = 6.022 × 1023 mol-1;
C = 2.99792458 × 108 m/s)

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