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The Equilibrium Constant for the Reaction AgBr(s) Ag+(aq)

question 58

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The equilibrium constant for the reaction AgBr(s) The equilibrium constant for the reaction AgBr(s)    Ag<sup>+</sup>(aq)  + Br<sup>- </sup>(aq)  is the solubility product constant, K<sub>sp</sub> = 7.7 × 10<sup>-13</sup> at 25°C. Calculate ΔG for the reaction when [Ag<sup>+</sup>] = 1.0 × 10<sup>-2 </sup><sup>M</sup> and [Br<sup>-</sup>] = 1.0 × 10<sup>-3 </sup><sup>M</sup>. Is the reaction spontaneous or nonspontaneous at these concentrations? (R = 8.314 J/K • mol)  A)  ΔG = 69.1 kJ/mol, nonspontaneous B)  ΔG = -69.1 kJ/mol, spontaneous C)  ΔG = 97.5 kJ/mol, spontaneous D)  ΔG = 40.6 kJ/mol, nonspontaneous E)  ΔG = -97.5 kJ/mol, nonspontaneous Ag+(aq) + Br- (aq) is the solubility product constant, Ksp = 7.7 × 10-13 at 25°C. Calculate ΔG for the reaction when [Ag+] = 1.0 × 10-2 M and [Br-] = 1.0 × 10-3 M. Is the reaction spontaneous or nonspontaneous at these concentrations? (R = 8.314 J/K • mol)


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