In a Parallel RLC Circuit, Where IR = IR, Max $\omega$

question 26

Multiple Choice

In a parallel RLC circuit, where IR = IR, max sin( $\omega$ t) , the current through the capacitor, IC, is:

• A)IC = -IC, max sin(\( \omega \)t).
• B)IC = IC, max sin(\( \omega \)t).
• C)IC = -IC, max cos(\( \omega \)t).
• D)IC = IC, max cos(\( \omega \)t).
• E)IC = IC, max tan(\( \omega \)t).

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