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A Uniform Rod of Mass M = 1 θ\theta = 40 °\degree

question 47

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A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by (1/3) ML2. If a force (F = 5.0 N, θ\theta = 40 °\degree ) acts as shown, what is the resulting angular acceleration about the pivot point?  A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by (1/3) ML2. If a force (F = 5.0 N,  \theta  = 40  \degree )  acts as shown, what is the resulting angular acceleration about the pivot point?   A) 16 rad/s2 B) 12 rad/s2 C) 14 rad/s2 D) 10 rad/s2 E) 33 rad/s2


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