$\text { Find the differential equation having the solution } \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( 4 x ) ^ { 2 n + 1 } } { ( 2 n + 1 ) ! } \text {. }$

Question

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The Answer of $\text { Find the differential equation having the solution } \sum _ { n = 0 } ^ { \infty } \frac { ( - 1 ) ^ { n } ( 4 x ) ^ { 2 n + 1 } } { ( 2 n + 1 ) ! } \text {. }$

A) $y ^ {tt } - 16 y = 0$

Definitions:

A) ytt−16y=0y ^ {tt } - 16 y = 0ytt−16y=0

Definitions:

A) $y ^ {tt } - 16 y = 0$