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Approximate the Sum of the Series by Using the First n=1(1)n+13ln(n+1)\sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } 3 } { \ln ( n + 1 ) }

question 88

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Approximate the sum of the series by using the first six terms. n=1(1) n+13ln(n+1) \sum _ { n = 1 } ^ { \infty } \frac { ( - 1 ) ^ { n + 1 } 3 } { \ln ( n + 1 ) }


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