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Find the Derivative of the Function g(x)=1x1t2+2dtg ( x ) = \int _ { 1 } ^ { x } \frac { 1 } { t ^ { 2 } + 2 } d t

question 77

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Find the derivative of the function.
g(x) =1x1t2+2dtg ( x ) = \int _ { 1 } ^ { x } \frac { 1 } { t ^ { 2 } + 2 } d t


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