Determine Whether the Series Is Convergent or Divergent$$\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$$

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The Answer of Determine Whether the Series Is Convergent or Divergent$$\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$$

Determine Whether the Series Is Convergent or Divergent $\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$

Definitions:

Determine Whether the Series Is Convergent or Divergent ∑n=1∞tan⁡−1nnn+6\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }n=1∑∞​nn+6​tan−1n​

Definitions:

Determine Whether the Series Is Convergent or Divergent $\sum _ { n = 1 } ^ { \infty } \frac { \tan ^ { - 1 } n } { n \sqrt { n + 6 } }$