Calculate the Mass of CO₂ (In Kilograms) Produced by the Combustion

Question

Examlex · Accepted Answer

The Answer is From Chapter 1, the combustion process is

\mathrm { C } _ { 2 } \mathrm { H } _ { 6 } \mathrm { O } + 3 \mathrm { O } _ { 2 } ightarrow 2 \mathrm { CO } _ { 2 } + 3 \mathrm { H } _ { 2 } \mathrm { O } + ext { heat }

Thus one mole of ethanol will yield two moles of

\mathrm { CO } _ { 2 }

. The molecular masses are

\mathrm { C } _ { 2 } \mathrm { H } _ { 6 } \mathrm { O } ightarrow 2 imes 12 + 6 + 16 = 46 \mathrm {~g} / \mathrm { mol }

\mathrm { CO } _ { 2 } ightarrow 12 + 2 imes 16 = 44 \mathrm {~g} / \mathrm { mol }

So

46 \mathrm {~g}

of ethanol will yield

88 \mathrm {~g}

of

\mathrm { CO } _ { 2 }

. Per

\mathrm { kg }

of ethanol this is

( 1 \mathrm {~kg} ) imes ( 88 \mathrm {~g} / 46 \mathrm {~g} ) =

1.91 \mathrm {~kg} ^ { \mathrm { kg } } \mathrm { CO } _ { 2 }

per

\mathrm { kg }

of ethanol.

Calculate the Mass of CO2 (In Kilograms) Produced by the Combustion