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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) 2cosx3=02 \cos x - \sqrt { 3 } = 0

question 82

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Solve the equation in the interval [0,2π)[ 0,2 \pi )
. 2cosx3=02 \cos x - \sqrt { 3 } = 0


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