If the Terminal Point Determined By $t$ Is $\left( \frac { 12 } { 13 } , - \frac { 5 } { 13 } \right)$

question 1

Multiple Choice

If the terminal point determined by $t$ is $\left( \frac { 12 } { 13 } , - \frac { 5 } { 13 } \right)$ , find $\sin t$ , $\cos t$ And $\tan t$

• A) \(\sin ( t ) = \frac { 12 } { 13 }\), \(\cos ( t ) = \frac { 5 } { 13 }\), \(\tan ( t ) = \frac { 5 } { 12 }\)
• B) \(\sin ( t ) = - \frac { 5 } { 13 }\), \(\cos ( t ) = \frac { 12 } { 13 }\), \(\tan ( t ) = - \frac { 5 } { 12 }\)
• C) \(\sin ( t ) = \frac { 5 } { 13 }\), \(\cos ( t ) = - \frac { 12 } { \Gamma 3 }\), \(\tan ( t ) = - \frac { 13 } { 12 }\)
• D) \(\sin ( t ) = - \frac { 5 } { 13 }\), \(\cos ( t ) = \frac { 12 } { 13 }\), \(\tan ( t ) = - \frac { 12 } { 5 }\)
• E) \(\sin ( t ) = - \frac { 5 } { 13 }\), \(\cos ( t ) = \frac { 12 } { 13 }\), \(\tan t = \frac { 12 } { 5 }\)

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