The Voltage Across an Inductor with Inductance of 510 MH$$v ( t ) = \left\{ \begin{array} { c }
0.05 t ^ { 2 } , \quad 0 \leq t

Question

The Voltage Across an Inductor with Inductance of 510 MH$$v ( t ) = \left\{ \begin{array} { c } 
0.05 t ^ { 2 } , \quad 0 \leq t < 5 \
0.05 ( t - 10 ) ^ { 2 } , \quad 5 \leq t < 10 \mathrm {~V} \
0 , \quad \text { otherwise }
\end{array} \right.$$

Examlex · Accepted Answer

The Answer is

i ( t ) = \frac { 1 } { L } \int _ { 0 } ^ { t } v ( \lambda ) d \lambda = \left\{ \begin{array} { c } 0.03268 t ^ { 3 } , \quad 0 \leq t < 5 \0.03268 t ^ { 3 } - 0.9804 t ^ { 2 } + 9.8039 t - 24.5098 , \quad 5 \leq t < 10 \mathrm {~A} \8.17 , \quad 10 \leq t\end{array} ight.

$i ( t ) = \frac { 1 } { L } \int _ { 0 } ^ { t } v ( \lambda ) d \lambda = \left\{ \begin{array} { c } 0.03268 t ^ { 3 } , \quad 0 \leq t < 5 \ 0.03268 t ^ { 3 } - 0.9804 t ^ { 2 } + 9.8039 t - 24.5098 , \quad 5 \leq t < 10 \mathrm {~A} \ 8.17 , \quad 10 \leq t \end{array} ight.$
$i ( t ) = \frac { 1 } { L } \int _ { 0 } ^ { t } v ( \lambda ) d \lambda = \left\{ \begin{array} { c } 0.03268 t ^ { 3 } , \quad 0 \leq t < 5 \ 0.03268 t ^ { 3 } - 0.9804 t ^ { 2 } + 9.8039 t - 24.5098 , \quad 5 \leq t < 10 \mathrm {~A} \ 8.17 , \quad 10 \leq t \end{array} ight.$

The Voltage Across an Inductor with Inductance of 510 MH

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