In the Circuit Shown Below, (A) Write a Mesh Equation$I _ { 1 }$

Question

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The Answer is

\begin{array} { l } - \mathrm { V } _ { 1 } + \mathrm { R } _ { 1 } \mathrm { I } _ { 1 } + \mathrm { R } _ { 2 } \left( \mathrm { I } _ { 1 } - \mathrm { I } _ { 2 } ight) = 0 \\mathrm { R } _ { 2 } \left( \mathrm { I } _ { 2 } - \mathrm { I } _ { 1 } ight) + \mathrm { R } _ { 3 } \mathrm { I } _ { 2 } + \mathrm { V } _ { 2 } = 0 \\mathrm {~V} _ { 3 } = \mathrm { R } _ { 2 } \left( \mathrm { I } _ { 1 } - \mathrm { I } _ { 2 } ight) \\mathrm { I } _ { 1 } = 1 \mathrm {~mA} , \mathrm { I } _ { 2 } = - 1 \mathrm {~mA} , \mathrm {~V} _ { 3 } = 3 \mathrm {~V}\end{array}

% Mesh Analysis clear all

\mathrm { V } 1 = 5 ; \mathrm { V } 2 = 6

;

\mathrm { R } 1 = 2000 ; \mathrm { R } 2 = 1500 ; \mathrm { R } 3 = 3000 ;

\begin{array}{l} ext { Syms II I2 } \{[I 1, I 2]= ext { Solve }(-\mathrm{V} 1+\mathrm{R} 1 * I 1+\mathrm{R} 2 *(I 1-I 2), \mathrm{R} 2 *(I 2-I 1)+\mathrm{R} 3 * I 2+\mathrm{V} 2, I 1, I 2)} \\mathrm{V} 3=\mathrm{R} 2 *(I 1-I 2) \I 1=\operatorname{vpa}(I 1,7) \ ext { I2 }=\operatorname{vpa}(I 2,7) \\mathrm{V} 3=\operatorname{vpa}(\mathrm{V} 3,7)\end{array}

Answers:

\begin{array} { l } 11 = \0.001 \12 = \- 0.001 \V 3 = \3.0\end{array}

In the Circuit Shown Below, (A) Write a Mesh Equation $I _ { 1 }$