Using the Rafter Table, Find the Length of Common Rafters

question 1

Short Answer

Using the rafter table, find the length of common rafters in the following problems. Express answers in feet and inches, correct to the nearest 1/8 inch.

$\begin{array}{c}\text { WINDOW SCHEDULE }\\\begin{array}{|c|c|c|l|l|l|l|l|}\hline \text { Symbol } & \text { Item } & \text { Quantity } & \begin{array}{c}\text { Type } \\\text { Window }\end{array} & \text { Rough Opening } & \text { Unit Size } & \begin{array}{c}\text { Manufacturer } \\\text { No. }\end{array} & \text { Remarks } \\\hline \text { A } & 1 & 1 & \text { Bay } & 9^{\prime}-9 ~~1/2^{\prime \prime} \times 5^{\prime}-4^{\prime \prime} & 9^{\prime}-6~~1/4^{\prime \prime} \times 4^{\prime}-11 ~~1/8^{\prime \prime} & \text { Jones } 1580 &\text { Radius } 10^{\prime}-4 ~~1/2{ }^{\prime \prime}\\\hline \text { B } & 2 & 4 & \text { Sliding } & 3^{\prime}-7~~1/4^{\prime \prime} \times 3^{\prime}-6 ~~1 / 4^{{\prime \prime}} & 3^{\prime}-5~~1/2^{\prime \prime} \times 3^{\prime \prime}-3~~1/ 2^{\prime \prime} & \text { Smith } 16285 &\text { Removable Sash}\\\hline \text { C } & 3 & 1 & \begin{array}{l}\text { Double } \\\text { Hung }\end{array} & 2^{\prime}-10~~1/8^{\prime \prime} \times 3^{\prime}-1~~1 / 8^{\prime \prime} & 2^{\prime}-8^{\prime \prime} \times 2^{\prime}-10^{\prime \prime} & \text { Jones } 1437 \\\hline \text { D } & 4 & 6 & \begin{array}{l}\text { Double } \\\text { Hung }\end{array} & 3^{\prime}-2~~1/8^{\prime \prime} \times 4^{\prime}-5~~1/3^{\prime \prime} & 3^{\prime}-0^{\prime \prime} \times 4^{\prime}-2^{\prime \prime} & \text { Jones } 1467 \\\hline \text { E } & 5 & 2 & \text { Casement } & 5^{\prime}-4^{\prime \prime} \times 1^{\prime}-8^{\prime \prime} & 4^{\prime}-11^{\prime} \times 1^{\prime}-3^{\prime \prime} & \text { Smith } 782 \mathrm{~A} \\\hline\end{array}\end{array}$ If the pitch is 1/4 what is the rise per foot of run?