Solve the System by the Method of Substitution $$\left\{ \begin{aligned}x & = \sqrt { y + 10 } \\3 x + 2 y & = - 20\end{aligned} \right.$$

question 41

Multiple Choice

Solve the system by the method of substitution. $$\left\{ \begin{aligned}x & = \sqrt { y + 10 } \\3 x + 2 y & = - 20\end{aligned} \right.$$

• A) \(( 0 , - 10 ) \left( - \frac { 3 } { 2 } , - \frac { 31 } { 4 } \right)\)
• B) \(\left( \frac { 3 } { 2 } , - \frac { 31 } { 4 } \right)\)
• C) \(( 0 , - 10 )\)
• D) \(( 0,10 ) \left( \frac { 3 } { 2 } , - \frac { 31 } { 4 } \right)\)
• E)no solution exist

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