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Exhibit 18-3 the Following Question(s) Pertain to the Reaction of Propene

question 24

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Exhibit 18-3 The following question(s) pertain to the reaction of propene (C3CHCH2) with hydrochloric acid. HCl+C3CHCH2CH3CHClCH3\mathrm{HCl}+\mathrm{C}_{3} \mathrm{CHCH}_{2} \leftrightarrows \mathrm{CH}_{3} \mathrm{CHClCH}_{3} A proposed mechanism for this chemical reaction is HCl+HClH2Cl2 (fast, equilibrium)  HCl+C3CHCH2CH3CHClCH3 (fast, equilibrium)  CH3CHClCH3+H2Cl2CH3CHClCH32HCl (slow)  \begin{array}{ll}\mathrm{HCl}+\mathrm{HCl} \leftrightarrows \mathrm{H}_{2} \mathrm{Cl}_{2}& \text { (fast, equilibrium) } \\\mathrm{HCl}+\mathrm{C}_{3} \mathrm{CHCH}_{2} \leftrightarrows \mathrm{CH}_{3} \mathrm{CHClCH}_{3}{ }^{*} & \text { (fast, equilibrium) } \\\mathrm{CH}_{3} \mathrm{CHClCH}_{3}{ }^{*}+\mathrm{H}_{2} \mathrm{Cl}_{2} \rightarrow \mathrm{CH}_{3} \mathrm{CHClCH}_{3} \rightarrow 2 \mathrm{HCl} & \text { (slow) }\end{array}

Refer to Exhibit 18-3. If the first step were the slow step, what would be the predicted order of the reaction with respect to propene?


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