Public Static Void Main(String Args[])

question 31

Essay

public static void main(String args[])
{
   int a, b;
   try
   {
      a = 0;
      b = 42 / a;
      System.out.println("This will not be printed.");
   }  
​
   catch (ArithmeticException e)
   {
      System.out.println("Division by zero.");
   }
   System.out.println("After catch statement.");
}
The program above includes a try block and a catch clause that processes the ArithmeticException generated by the division-by-zero error. Explain how the try and catch blocks operate, and what the output will be following program execution.

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