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Calculate [Ba2+] when 35.00 mL of 0.2000 M EDTA is added to 50.00 mL of 0.1000 M Ba2+ in the presence of 0.1 M nitrilotriacetate. = 1.48 x 10−4.
= 0.30 for pH 10.Kf = 7.59 × 107 for BaY2−.
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