The Equilibrium Expression for the Ionization of a Weak Monoprotic

question 178

Multiple Choice

The equilibrium expression for the ionization of a weak monoprotic acid, HA, in water is:

• A) K_a = [HA]/[OH^-][H₃O⁺]
• B) K_a = [OH^-][H₃O⁺]/[HA]
• C) K_a = [H₃O⁺][HA]/[A^-]
• D) K_a = [H₃O⁺][A^-]/[HA]
• E) K_a = [HA]/[H₃O⁺][A^-]

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