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Calculate the Standard Enthalpy of Formation of Liquid Methanol, CH3OH(l)

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Calculate the standard enthalpy of formation of liquid methanol, CH3OH(l) , using the following information: C (graph)  +O2CO2(g) ΔH=393.5 kJ/molH2(g) +(1/2) O2H2O(l) ΔH=285.8 kJ/molCH3OH(l) +(3/2) O2(g) CO2( g) +2H2O(l) ΔH=726.4 kJ/mol\begin{array}{ll}\mathrm{C} \text { (graph) }+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}(\mathrm{g}) & \Delta \mathrm{H}^{\circ}=-393.5 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{H}_{2}(\mathrm{g}) +(1 / 2) \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-285.8 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{CH}_{3} \mathrm{OH}(\mathrm{l}) +(3 / 2) \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g}) +2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-726.4 \mathrm{~kJ} / \mathrm{mol}\end{array}


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