The Reaction Between Selenous Acid and the Iodide Ion in Acid

question 75

Multiple Choice

The reaction between selenous acid and the iodide ion in acid solution is
H₂SeO₃(aq) + 6I^-(aq) + 4H⁺(aq) → Se(s) + 2I₃^-(aq) + 3H₂O(l)
The data in the following table were measured at 0°C.
Experiment
[H₂SeO₃]₀ (M)
[H⁺]₀ (M)
[I^-]₀ (M)
Initial Rate [mol/(L ∙ s) ]
1
1) 00 × 10^-4
2) 00 × 10^-2
3) 00 × 10^-2
5) 30 × 10^-7
2
2) 00 × 10^-4
2) 00 × 10^-2
3) 00 × 10^-2
1) 06 × 10^-6
3
3) 00 × 10^-4
4) 00 × 10^-2
3) 00 × 10^-2
6) 36 × 10^-6
4
3) 00 × 10^-4
8) 00 × 10^-2
3) 00 × 10^-2
2) 54 × 10^-5
5
3) 00 × 10^-4
8) 00 × 10^-2
6) 00 × 10^-2
2) 04 × 10^-4
6
2) 00 × 10^-4
2) 00 × 10^-2
6) 00 × 10^-2
8) 48 × 10^-6
What is the rate constant for this reaction?

• A)1.5 × 10⁴ L⁵/(mol⁵ ∙ s)
• B)1.5 × 10¹⁰ L⁵/(mol⁵ ∙ s)
• C)4.9 × 10⁵ L⁵/(mol⁵ ∙ s)
• D)294 L⁵/(mol⁵ ∙ s)
• E)8.8 L⁵/(mol⁵ ∙ s)

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