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What Is the Equilibrium Concentration of Amide Ion (NH2-)in Liquid

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What is the equilibrium concentration of amide ion (NH2-) in liquid ammonia at 25°C? ("am" = dissolved in ammonia)
2NH3(l) What is the equilibrium concentration of amide ion (NH<sub>2</sub><sup>-</sup>) in liquid ammonia at 25°C? ( am  = dissolved in ammonia)  2NH<sub>3</sub>(l)    NH<sub>4</sub><sup>+</sup>(am) + NH<sub>2</sub><sup>-</sup>(am) ; K<sub>c</sub> = 1.8 × 10<sup>-24</sup> at 25°C A) 2.6 × 10<sup>-12</sup> M B) 3.6 × 10<sup>-24</sup> M C) 1.3 × 10<sup>-12</sup> M D) 1.8 × 10<sup>-24</sup> M E) 9.0 × 10<sup>-25</sup> M
NH4+(am) + NH2-(am) ; Kc = 1.8 × 10-24 at 25°C


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