Combine the Reactions: P₄(s)+ 6 Cl₂(g)→ 4 PCl₃(g)Δ_rH°₂₉₈ = -1225.0 KJ/mol

question 1

Multiple Choice

Combine the reactions:
P₄(s) + 6 Cl₂(g) → 4 PCl₃(g) Δ_rH°₂₉₈ = -1225.0 kJ/mol
PCl₃(g) + 3 H₂O(l) → H₃PO₃(aq) + 3 HCl(g) = -853.5 kJ/mol
2 H₂(g) + O₂(g) → 2 H₂O(l) = -571.5 kJ/mol
H₂(g) + Cl₂(g) → 2 HCl(g) = -184.9 kJ/mol
To obtain the reaction: P₄(s) + 6 H₂(g) + 6 O₂(g) → 4 H₃PO₃(aq) .
What is the value of Δ_rH°₂₉₈ for this reaction?

• A)-2465.1 kJ/mol
• B)-6958.6 kJ/mol
• C)-2834.9 kJ/mol
• D)-9177.4 kJ/mol
• E)8605.9 kJ/mol

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