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For the Reaction: 2 N2O5(g)→ 4 NO2(g)+ O2(g)the Rate Law

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For the reaction: 2 N2O5(g) → 4 NO2(g) + O2(g) the rate law is:
For the reaction: 2 N<sub>2</sub>O<sub>5</sub>(g) → 4 NO<sub>2</sub>(g) + O<sub>2</sub>(g) the rate law is:   = k[N<sub>2</sub>O<sub>5</sub>] At 300 K,the half-life is 2.50 × 10<sup>4</sup> seconds and the activation energy is 103.3 kJ/mol O<sub>2</sub>.At the time when N<sub>2</sub>O<sub>5</sub> is being consumed at a rate of 1.2 × 10<sup>-4</sup> M/s,what is the rate at which NO<sub>2</sub> is being formed? A) 1.2 × 10<sup>-4</sup> M/s B) 2.4 × 10<sup>-4</sup> M/s C) 6.0 × 10<sup>-5</sup> M/s D) 3.0 × 10<sup>-5</sup> M/s E) 4.8 × 10<sup>-4</sup> M/s= k[N2O5]
At 300 K,the half-life is 2.50 × 104 seconds and the activation energy is 103.3 kJ/mol O2.At the time when N2O5 is being consumed at a rate of 1.2 × 10-4 M/s,what is the rate at which NO2 is being formed?

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