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For the reaction: 2 N2O5(g) → 4 NO2(g) + O2(g) the rate law is: = k[N2O5]
At 300 K,the half-life is 2.50 × 104 seconds and the activation energy is 103.3 kJ/mol O2.At the time when N2O5 is being consumed at a rate of 1.2 × 10-4 M/s,what is the rate at which NO2 is being formed?
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