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Pentaborane B5H9(s) burns vigorously in O2 to give B2O3(s) and H2O(l) .Calculate Hrxn for the combustion of 5.00 mol of B5H9.
H°f[B2O3(s) ] = -1,273.5 kJ/mol
H°f[B5H9(s) ] = 73.2 kJ/mol
H°f[H2O(l) ] = -285.8 kJ/mol
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