The Equilibrium Constant at 427°C for the Reaction N₂(g)+ 3H₂(g) $\Delta$

question 124

Multiple Choice

The equilibrium constant at 427°C for the reaction N₂(g) + 3H₂(g) 2NH₃(g) is K_p = 9.4 × 10^-5.Calculate the value of $\Delta$ G° for the reaction under these conditions.

• A)-33 kJ/mol
• B)-54 kJ/mol
• C)54 kJ/mol
• D)33 kJ/mol
• E)1.3 J/mol

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