For the Reaction H₂O₂(g) $\rarr$ H₂O(g)+ ¹/₂O₂(g) $\Delta$ H° = -106 KJ/mol And

question 36

Short Answer

For the reaction H₂O₂(g) $\rarr$ H₂O(g)+ ¹/₂O₂(g), $\Delta$ H° = -106 kJ/mol and $\Delta$ S° = 58 J/K·mol at 25°C.Calculate $\Delta$ G° for this reaction at this temperature.

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