At 25°C, the Standard Enthalpy of Formation of KCl(s)is -435 $\Delta$

question 106

Multiple Choice

At 25°C, the standard enthalpy of formation of KCl(s) is -435.87 kJ/mol. When one mole of KCl(s) is formed by reacting potassium vapor and chlorine gas at 25°C, the standard enthalpy of reaction is -525.86 kJ/mol. Find $\Delta$ H° for the sublimation of potassium, K(s) $\rarr$ K(g) , at 25°C.

• A)-345.88 kJ/mol
• B)45.00 kJ/mol
• C)345.88 kJ/mol
• D)89.99 kJ/mol
• E)-525.86 kJ/mol

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