The Equilibrium Constant Expression for the Reaction 2BrF₅(g)

question 23

Multiple Choice

The equilibrium constant expression for the reaction 2BrF₅(g) Br₂(g) + 5F₂(g) is

• A)K_c = [Br₂] [F₂] / [BrF₅]
• B)K_c = [Br₂] [F₂]⁵ / [BrF₅]²
• C)K_c = [Br₂] [F₂]² / [BrF₅]⁵
• D)K_c = [BrF₅]² / [Br₂][F₂]⁵
• E)K_c = 2[BrF₅]² / ([Br₂] * 5[F₂]⁵)

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