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Given: 4 NO2(g)+ O2(g)→ 2 N2O5(g)ΔH° = -110

question 56

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Given: 4 NO2(g) + O2(g) → 2 N2O5(g) ΔH° = -110.2 kJ find ΔH° for 8 N2O5(g) → 16 NO2(g) + 4 O2(g) .


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