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Calculate the Value of the Equilibrium Constant for the Reaction

question 76

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Calculate the value of the equilibrium constant for the reaction AgCl(s) + 2NH3(aq) Calculate the value of the equilibrium constant for the reaction AgCl(s) + 2NH<sub>3</sub>(aq)    Ag(NH<sub>3</sub>) <sub>2</sub>+(aq) + Cl<font face= symbol ><sup></sup></font>(aq)  Given K<sub>sp</sub> = 1.6 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>10</sup> for silver chloride and K<sub>f</sub> = 1.6 <font face= symbol ></font> 10<sup>7</sup> for the ammonia complex of Ag<sup>+</sup> ions,Ag(NH<sub>3</sub>) <sup>2+</sup>. A) 1.0 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>17 </sup> B) 6.3 <font face= symbol ></font> 10<sup>9 </sup> C) 6.3 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>8 </sup> D) 1.0 <font face= symbol ></font> 10<sup>17 </sup> E) 2.6 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>3 </sup> Ag(NH3) 2+(aq) + Cl(aq)
Given Ksp = 1.6 1010 for silver chloride and Kf = 1.6 107 for the ammonia complex of Ag+ ions,Ag(NH3) 2+.


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