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Calculate the Equilibrium Constant for the Following Reaction at 25 \circ

question 39

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Calculate the equilibrium constant for the following reaction at 25 \circ C,
2 IO3-(aq) + 5 Hg(  Calculate the equilibrium constant for the following reaction at 25 <sup> \circ </sup>C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq)  \to  I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  Given the following thermodynamic information. IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup>  \to  I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  ~~~~~~~~ E<sup> \circ </sup> = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Hg(   )  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ E<sup> \circ </sup>= +0.86 V A)  3  \times  10<sup>-58</sup> B)  6  \times  10<sup>5</sup> C)  3  \times  10<sup>11</sup> D)  6  \times  10<sup>28</sup> E)  3  \times  10<sup>57</sup> ) + 12 H+(aq) \to I2(s) + 5 Hg2+(aq) + 6 H2O(  Calculate the equilibrium constant for the following reaction at 25 <sup> \circ </sup>C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq)  \to  I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  Given the following thermodynamic information. IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup>  \to  I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  ~~~~~~~~ E<sup> \circ </sup> = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Hg(   )  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ E<sup> \circ </sup>= +0.86 V A)  3  \times  10<sup>-58</sup> B)  6  \times  10<sup>5</sup> C)  3  \times  10<sup>11</sup> D)  6  \times  10<sup>28</sup> E)  3  \times  10<sup>57</sup> )
Given the following thermodynamic information.
IO3-(aq) + 6 H+(aq) + 5 e- \to I2(s) + 3 H2O(  Calculate the equilibrium constant for the following reaction at 25 <sup> \circ </sup>C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq)  \to  I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  Given the following thermodynamic information. IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup>  \to  I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  ~~~~~~~~ E<sup> \circ </sup> = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Hg(   )  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ E<sup> \circ </sup>= +0.86 V A)  3  \times  10<sup>-58</sup> B)  6  \times  10<sup>5</sup> C)  3  \times  10<sup>11</sup> D)  6  \times  10<sup>28</sup> E)  3  \times  10<sup>57</sup> )         ~~~~~~~~ E \circ = +1.20 V
Hg2+(aq) + 2 e- \to Hg(  Calculate the equilibrium constant for the following reaction at 25 <sup> \circ </sup>C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq)  \to  I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  Given the following thermodynamic information. IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup>  \to  I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  ~~~~~~~~ E<sup> \circ </sup> = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Hg(   )  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ E<sup> \circ </sup>= +0.86 V A)  3  \times  10<sup>-58</sup> B)  6  \times  10<sup>5</sup> C)  3  \times  10<sup>11</sup> D)  6  \times  10<sup>28</sup> E)  3  \times  10<sup>57</sup> )         ~~~~~~~~        ~~~~~~~~        ~~~~~~~~        ~~~~~~~~ E \circ = +0.86 V


Definitions:

Achiral

Describes a molecule that is superposable on its mirror image and does not exhibit chirality.

Meso Compound

A molecule with multiple stereocenters and an internal plane of symmetry, making it achiral despite its stereogenic centers.

Diastereomer

Stereoisomers that are not mirror images of each other, differing in the spatial arrangement of atoms around one or more asymmetric centers.

Achiral

A term describing molecules that are superimposable on their mirror images, indicating they do not possess handedness or chirality.

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