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Estimate the Rotational Energy (In EV) for a Diatomic Hydrogen

question 10

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Estimate the rotational energy (in eV) for a diatomic hydrogen molecule in the l = 2 quantum state. (The equilibrium separation for the H2 molecule is 0.074 nm.) (1 eV = 1.60 × 10-19 J, h = 6.626 × 10-34 J ∙ s, Estimate the rotational energy (in eV)  for a diatomic hydrogen molecule in the l = 2 quantum state. (The equilibrium separation for the H<sub>2</sub> molecule is 0.074 nm.)  (1 eV = 1.60 × 10<sup>-19</sup> J, h = 6.626 × 10<sup>-34</sup> J ∙ s,  = 1.055 × 10<sup>-34 </sup>J ∙ s, <sup>m</sup>H ≈ <sup>m</sup>proton = 1.67 × 10<sup>-27</sup> kg)  A)  0.011 eV B)  0.026 eV C)  0.032 eV D)  0.046 eV E)  0.055 eV= 1.055 × 10-34 J ∙ s, mH ≈ mproton = 1.67 × 10-27 kg)


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