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Solve the System by the Method of Elimination and Check {0.05x0.03y=0.290.07x+0.02y=0.22\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.

question 49

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Solve the system by the method of elimination and check any solutions algebraically. ​​ {0.05x0.03y=0.290.07x+0.02y=0.22\left\{ \begin{array} { l } 0.05 x - 0.03 y = 0.29 \\0.07 x + 0.02 y = 0.22\end{array} \right.

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