The Solution of the Eigenvalue Problem in the Previous Problem $\lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X = \sin ( ( n - 1 / 2 ) \pi x / L )$

question 33

Multiple Choice

The solution of the eigenvalue problem in the previous problem is

• A) \(\lambda = ( ( n - 1 / 2 ) \pi / L ) ^ { 2 } , X = \sin ( ( n - 1 / 2 ) \pi x / L )\)
• B) \(\sqrt { \lambda } / h = \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )\)
• C) \(\lambda = ( n \pi / L ) ^ { 2 } , X = \sin ( n \pi x / L )\)
• D) \(\sqrt { \lambda } / h = - \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )\)
• E) \(\sqrt { \lambda } h = - \tan ( \sqrt { \lambda } L ) , X = \sin ( \sqrt { \lambda } x )\)

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