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Water Flows from a Tank of Constant Cross-Sectional Area 50 ft2\mathrm{ft}^{2}

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Water flows from a tank of constant cross-sectional area 50 ft2\mathrm{ft}^{2} through an orifice of constant cross-sectional area 14\frac{1}{4} ft2\mathrm{ft}^{2} located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t sec later it was given by the equation 2h+125t220=00t50202 \sqrt{h}+\frac{1}{25} t-2 \sqrt{20}=0 \quad \quad \quad 0 \leq t \leq 50 \sqrt{20} How fast was the height of the water decreasing when its height was 2 ft?  Water flows from a tank of constant cross-sectional area 50  \mathrm{ft}^{2}  through an orifice of constant cross-sectional area  \frac{1}{4}   \mathrm{ft}^{2}  located at the bottom of the tank. Initially, the height of the water in the tank was 20 ft, and t sec later it was given by the equation  2 \sqrt{h}+\frac{1}{25} t-2 \sqrt{20}=0 \quad \quad \quad 0 \leq t \leq 50 \sqrt{20}  How fast was the height of the water decreasing when its height was 2 ft?   A)   100 \sqrt{5}-50 \sqrt{2}  ft/sec B)   100 \sqrt{5}-50 \sqrt{2}  ft/sec. C)   \frac{2}{25}  ft/sec D)   \frac{\sqrt{2}}{25}  ft/sec


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