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Phosphoric Acid Is a Triprotic Acid in Water,ionizing in the Following

question 125

Multiple Choice

Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H₃PO₄ + H₂O $\leftrightarrows$ H₂PO₄^- + H₃O⁺ $Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H3PO4 + H2O \leftrightarrows H2PO4- + H3O+ = 7.11 *10-3 H2PO4- + H2O \leftrightarrows HPO42- + H3O+ = 6.32 *10-8 HPO42- + H2O \leftrightarrows PO43- + H3O+ = 4.5 *10-13 What is the pH of a 0.20 M Na3PO4 solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82$ = 7.11 *10^-³
H₂PO₄^- + H₂O $\leftrightarrows$ HPO₄²^- + H₃O⁺
$Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H3PO4 + H2O \leftrightarrows H2PO4- + H3O+ = 7.11 *10-3 H2PO4- + H2O \leftrightarrows HPO42- + H3O+ = 6.32 *10-8 HPO42- + H2O \leftrightarrows PO43- + H3O+ = 4.5 *10-13 What is the pH of a 0.20 M Na3PO4 solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82$ = 6.32 *10^-⁸
HPO₄²^- + H₂O $\leftrightarrows$ PO₄³^- + H₃O⁺
$Phosphoric acid is a triprotic acid in water,ionizing in the following sequential steps: H3PO4 + H2O \leftrightarrows H2PO4- + H3O+ = 7.11 *10-3 H2PO4- + H2O \leftrightarrows HPO42- + H3O+ = 6.32 *10-8 HPO42- + H2O \leftrightarrows PO43- + H3O+ = 4.5 *10-13 What is the pH of a 0.20 M Na3PO4 solution? A) 1.66 B) 5.82 C) 10.50 D) 12.75 E) 12.82$ = 4.5 *10^-¹³
What is the pH of a 0.20 M Na₃PO₄ solution?

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