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For the Equilibrium 2 NOBr(g) \leftrightarrows 2 NO(g)+ Br2(g),Kc = 1 ×\times

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For the equilibrium 2 NOBr(g) \leftrightarrows 2 NO(g) + Br2(g) ,Kc = 1.56 ×\times 10-3 at 300.0 K.What is Kp at 300.0 K for the equilibrium,NO(g) +  For the equilibrium 2 NOBr(g)  \leftrightarrows  2 NO(g) + Br<sub>2</sub>(g) ,K<sub>c</sub> = 1.56  \times  10<sup>-3</sup> at 300.0 K.What is K<sub>p</sub> at 300.0 K for the equilibrium,NO(g) +   Br<sub>2</sub>(g)  \leftrightarrows   NOBr(g) ? A) 5.10 B) 126 C) 1.58  \times 10<sup>4</sup> D) 0.0384 E) 26.0 Br2(g) \leftrightarrows NOBr(g) ?

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