Jane Can Accept That $\Delta$ G $\degree$ = -RT Ln K, but She Cannot Reconcile the Relationship

question 19

Multiple Choice

Jane can accept that $\Delta$ G $\degree$ = -RT ln K, but she cannot reconcile the relationship between $\Delta$ S $\degree$ and ln K. Please explain it to her.

• A) (\(\Delta\)S\(\degree\) = R ln K - \(\Delta\)H\(\degree\)/T)
• B) (\(\Delta\)S\(\degree\) = +ln (K/R) + \(\Delta\)H\(\degree\)/T)
• C) (\(\Delta\)S\(\degree\) = +R ln (K/T) + \(\Delta\)H\(\degree\))
• D) (\(\Delta\)S\(\degree\)= +R ln (K) + \(\Delta\)H\(\degree\)/T)
• E) (\(\Delta\)S\(\degree\) = -R ln (K) + \(\Delta\)H\(\degree\)/T)

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