When 100 Mol of a Pure Liquid Is Vaporized at a a Constant

question 38

Multiple Choice

When 1.00 mol of a pure liquid is vaporized at a constant pressure of 1.06 atm and at its boiling point of 332.6 K, 32.16 kJ of energy (heat) is absorbed and the volume change is 27.44 L. What is ΔH for this process? (1 L-atm = 101.3 J)

• A) -35.11 kJ
• B) 35.11 kJ
• C) 29.21 kJ
• D) -29.21 kJ
• E) 32.16 kJ

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