Why Is a Terminal Alkyne Favored When Sodium Amide (NaNH₂)

question 100

Multiple Choice

Why is a terminal alkyne favored when sodium amide (NaNH₂) is used in an elimination reaction with 2,3-dichlorohexane?

• A) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.
• B) The resonance favors the formation of the terminal rather than internal alkyne.
• C) The positions of the Cl atoms induce the net formation of the terminal alkyne.
• D) The terminal alkyne is more stable than the internal alkyne and is naturally the favored product.
• E) The terminal alkyne is not favored in this reaction.

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