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Calculate the Equilibrium Constant for the Following Reaction at 25

question 22

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Calculate the equilibrium constant for the following reaction at 25 °C, 2 IO3-(aq) + 5 Hg( Calculate the equilibrium constant for the following reaction at 25 °C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq) → I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  The standard reduction potentials are as follows: IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup> → I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  E° = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Hg(   )  E° = +0.86 V A)  3 × 10<sup>-58</sup> B)  6 × 10<sup>5</sup> C)  3 × 10<sup>11</sup> D)  6 × 10<sup>28</sup> E)  3 × 10<sup>57</sup> ) + 12 H+(aq) → I2(s) + 5 Hg2+(aq) + 6 H2O( Calculate the equilibrium constant for the following reaction at 25 °C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq) → I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  The standard reduction potentials are as follows: IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup> → I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  E° = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Hg(   )  E° = +0.86 V A)  3 × 10<sup>-58</sup> B)  6 × 10<sup>5</sup> C)  3 × 10<sup>11</sup> D)  6 × 10<sup>28</sup> E)  3 × 10<sup>57</sup> )
The standard reduction potentials are as follows:
IO3-(aq) + 6 H+(aq) + 5 e- → I2(s) + 3 H2O( Calculate the equilibrium constant for the following reaction at 25 °C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq) → I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  The standard reduction potentials are as follows: IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup> → I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  E° = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Hg(   )  E° = +0.86 V A)  3 × 10<sup>-58</sup> B)  6 × 10<sup>5</sup> C)  3 × 10<sup>11</sup> D)  6 × 10<sup>28</sup> E)  3 × 10<sup>57</sup> )
E° = +1.20 V
Hg2+(aq) + 2 e- → Hg( Calculate the equilibrium constant for the following reaction at 25 °C, 2 IO<sub>3</sub><sup>-</sup>(aq) + 5 Hg(   ) + 12 H<sup>+</sup>(aq) → I<sub>2</sub>(s) + 5 Hg<sup>2+</sup>(aq) + 6 H<sub>2</sub>O(   )  The standard reduction potentials are as follows: IO<sub>3</sub><sup>-</sup>(aq) + 6 H<sup>+</sup>(aq) + 5 e<sup>-</sup> → I<sub>2</sub>(s) + 3 H<sub>2</sub>O(   )  E° = +1.20 V Hg<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Hg(   )  E° = +0.86 V A)  3 × 10<sup>-58</sup> B)  6 × 10<sup>5</sup> C)  3 × 10<sup>11</sup> D)  6 × 10<sup>28</sup> E)  3 × 10<sup>57</sup> )
E° = +0.86 V


Definitions:

Effective Body Mechanics

Techniques used to move the body that minimize the risk of injury and improve performance, essential in, e.g., lifting and moving objects safely.

Effective Lifting Techniques

Methods or practices of safely lifting and moving heavy objects or persons, particularly used in healthcare to prevent injury.

Correct Posture

The alignment of the body in a manner that properly supports the body's structures, reducing stress and strain.

Maximal Muscle Strength

The greatest force that a muscle or muscle group can exert in a single effort.

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