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TABLE 14-6
One of the Most Common Questions of Prospective

question 102

Multiple Choice

TABLE 14-6
One of the most common questions of prospective house buyers pertains to the average cost of heating in dollars (Y) . To provide its customers with information on that matter, a large real estate firm used the following 4 variables to predict heating costs: the daily minimum outside temperature in degrees of Fahrenheit (X1) , the amount of insulation in inches (X2) , the number of windows in the house (X3) , and the age of the furnace in years (X4) . Given below are the EXCEL outputs of two regression models.
 Model 1 Regression Statistics  R Square 0.8080 AdjustedR S quare 0.7568 Observations 20\begin{array}{ll}\text { Model } 1 \\\text { Regression Statistics } \\\hline \text { R Square }& 0.8080 \\\text { AdjustedR S quare }& 0.7568 \\\text { Observations } &20 \end{array}

ANOVA
 df SSMSF Signuficance F  Regression 4169503.424142375.8615.78742.96869E05 Residual 1540262.32592684.155 Total 19209765.75\begin{array}{lrrccc} & \text { df } &{S S} & M S & F & \text { Signuficance F } \\\hline \text { Regression } & 4 & 169503.4241 & 42375.86 & 15.7874 & 2.96869 E-05 \\\text { Residual } & 15 & 40262.3259 & 2684.155 & & \\\text { Total } & 19 & 209765.75 & & & \\\hline\end{array}

 Standard LowerUpper CoefficientsError t Stat p -value90.0%90.0% Intercept 421.427777.86145.41257.2E05284.9327557.9227 X1 (Temperature) 4.50980.81295.54765.58E055.93493.0847X2 (Insulation)  14.90295.05082.95050.009923.75736.0485 X3 (Windows)  0.21514.86750.04420.96538.31818.7484 X4 (Furnace Age) 6.37804.10261.55460.14080.814013.5702\begin{array}{lrrrrrrr} && \text { Standard } & & \text {Lower} & \text {Upper }\\& \text {Coefficients} & \text {Error} & \text { t Stat } & \text {p -value} & 90.0 \% & 90.0 \% \\ \hline \text { Intercept }& 421.4277 & 77.8614 & 5.4125 & 7.2 \mathrm{E}-05& 284.9327 & 557.9227 \\ \text { X{1} (Temperature) } & -4.5098 & 0.8129 & -5.5476 &5.58 \mathrm{E}-05 & -5.9349 & -3.0847 \\ \text {X{2} (Insulation) }& -14.9029 & 5.0508 & -2.9505 & 0.0099 & -23.7573 & -6.0485 \\ \text { X{3} (Windows) }& 0.2151 & 4.8675 & 0.0442 & 0.9653 & -8.3181 & 8.7484 \\ \text { X{4} (Furnace Age) } & 6.3780 & 4.1026 & 1.5546 & 0.1408 & -0.8140 & 13.5702 \\\hline\end{array}

 Model 2Regression StatisticsR Square 0.7768Adjusted R Square 0.7506Observations 20\begin{array}{ll} \text { Model 2} \\\hline \text {Regression Statistics} \\\hline \text {R Square }& 0.7768\\ \text {Adjusted R Square }&0.7506 \\ \text {Observations }& 20 \\\hline\end{array}
ANOVA
 d f SS  MS SS Significance F Regression2162958.227781479.1129.59232.9036E06Residual 1746807.52222753.384Total 19209765.75\begin{array}{lrrrcc}\hline & \text { d f} & \text { SS } & \text { MS } & \text {SS } & \text {Significance F } \\\hline \text {Regression} & 2 & 162958.2277 & 81479.11 & 29.5923 & 2.9036 \mathrm{E}-06 \\ \text {Residual }& 17 & 46807.5222 & 2753.384 & & \\ \text {Total }& 19 & 209765.75 & & & \\\hline\end{array}

 Standard  Lower UpperCoefficients  Error  t Stat  p -value95%95%Intercept 489.322743.982611.12533.17E09396.5273582.1180 X1 (Temperature)  5.11030.69517.35151.13E066.57693.6437 X2 (Insulation)  14.71954.88643.01230.007825.02904.4099\begin{array}{lcccccc} && \text { Standard } & &\text { Lower} &\text { Upper} \\& \text {Coefficients }&\text { Error }&\text { t Stat }& \text { p -value} &95 \%& 95 \% \\\hline \text {Intercept }& 489.3227 & 43.982611 .1253 &3.17 \mathrm{E}-09& 396.5273 & 582.1180 \\\text { X{1} (Temperature) }& -5.1103 & 0.6951-7.3515 & 1.13 \mathrm{E}-06 & -6.5769 & -3.6437 \\\text { X{2} (Insulation) }& -14.7195 & 4.8864-3.0123 & 0.0078 & -25.0290 & -4.4099 \\\hline\end{array}

-Referring to Table 14-6 and allowing for a 1% probability of committing a type I error, what is the decision and conclusion for the test H0 :?1 = ?2 = ?3 = ?4 = 0 versus H1 : At least one ?j ? 0, j = 1, 2,...,4 using Model 1?


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