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Solve the Problem D=24[1cos1(tanitanθ)π]\mathrm { D } = 24 \left[ 1 - \frac { \cos ^ { - 1 } ( \tan \mathrm { i } \tan \theta ) } { \pi } \right]

question 263

Short Answer

Solve the problem.
-The formula
D=24[1cos1(tanitanθ)π]\mathrm { D } = 24 \left[ 1 - \frac { \cos ^ { - 1 } ( \tan \mathrm { i } \tan \theta ) } { \pi } \right]
can be used to approximate the number of hours of daylight when the declination of the sun is ii ^ { \circ } at a location θ\theta ^ { \circ } latitude for any date between the vernal equinox and autumnal equinox. To use this formula, cos1\cos ^ { - 1 } (tan i tan θ\theta ) must be expressed in radians. Approximate the number of hours of daylight in Fargo, North Dakota, (4652'north latitude) for vernal equinox (i=0)\left( \mathrm { i } = 0 ^ { \circ } \right) . orth


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