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For the reaction CuS(s)+ H2(g)
H2S(g)+ Cu(s),
G°f (CuS)= -53.6 kJ/mol
G°f (H2S)= -33.6 kJ/mol
H°f (CuS)= -53.1 kJ/mol
H°f (H2S)= -20.6 kJ/mol
Calculate the value of the equilibrium constant (Kp)at 798 K and 1 atm pressure.
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