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Calculate the energy change for the formation of MgBr2(s) from its elements in their standard states: Mg(s) + Br2(l) → MgBr2(s) ?
Mg(s) → Mg(g) +147.1 kJ/mol
Mg(g) → Mg+(g) + e- +737.8 kJ/mol
Mg+(g) → Mg2+(g) + e- +1451 kJ/mol
Br2(l) → Br2(g) +30.9 kJ/mol
1/2 Br2(g) → Br(g) +112.0 kJ/mol
Br(g) + e- → Br-(g) -325.0 kJ/mol
MgBr2(s) → Mg2+(g) + 2Br-(g) +2440 kJ/mol
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