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Calculate the cell potential at 25°C for the cell Fe(s) ∣ (Fe2+(0.100 M) ∣∣ Pd2+(1.0 × 10-5 M) ∣ Pd(s)
Given that the standard reduction potential for Fe2+/Fe is -0.45 V and for Pd2+/Pd is +0.95 V.
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