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The Equilibrium Constant, Kc , for the Decomposition of COBr2

question 72

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The equilibrium constant, Kc , for the decomposition of COBr2 COBr2(g) The equilibrium constant, K<sub>c </sub>, for the decomposition of COBr<sub>2</sub> <sub> </sub>COBr<sub>2</sub>(g)    CO(g)  + Br<sub>2</sub>(g)  Is 0.190. What is K<sub>c</sub> for the following reaction? 2CO(g)  + 2Br<sub>2</sub>(g)    2COBr<sub>2</sub>(g)  A)  0.0361 B)  2.63 C)  5.62 D)  10.5 E)  27.7 CO(g) + Br2(g)
Is 0.190. What is Kc for the following reaction?
2CO(g) + 2Br2(g) The equilibrium constant, K<sub>c </sub>, for the decomposition of COBr<sub>2</sub> <sub> </sub>COBr<sub>2</sub>(g)    CO(g)  + Br<sub>2</sub>(g)  Is 0.190. What is K<sub>c</sub> for the following reaction? 2CO(g)  + 2Br<sub>2</sub>(g)    2COBr<sub>2</sub>(g)  A)  0.0361 B)  2.63 C)  5.62 D)  10.5 E)  27.7 2COBr2(g)


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