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Given the Following Acid Dissociation Constants: Ka (H3PO4)= 7

question 95

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Given the following acid dissociation constants: Ka (H3PO4) = 7.5 × 10-3
Ka (NH4+) = 5.6 × 10-10
Determine the equilibrium constant for the reaction below at 25 °C.
H3PO4(aq) + NH3(aq) Given the following acid dissociation constants: K<sub>a</sub> (H<sub>3</sub>PO<sub>4</sub>) = 7.5 × 10<sup>-3</sup> K<sub>a</sub> (NH<sub>4</sub><sup>+</sup>) = 5.6 × 10<sup>-10</sup> Determine the equilibrium constant for the reaction below at 25 °C. H<sub>3</sub>PO<sub>4</sub>(aq) + NH<sub>3</sub>(aq)    NH<sub>4</sub><sup>+</sup>(aq) + H<sub>2</sub>PO<sub>4</sub>−(aq)  A)  4.2 × 10<sup>-12</sup> B)  7.5 × 10<sup>-8</sup> C)  4.2 × 10<sup>2</sup> D)  1.3 × 10<sup>7</sup> E)  2.4 × 10<sup>11</sup> NH4+(aq) + H2PO4−(aq)


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